assume boom weighs 2450 Newtons
HAVE to Know Length of boom (I will call it L)
clockwise moments about base of boom
5000 L cos 60 + 2450 (39) cos 60
counterclockwise moments
T L sin 60
so
T = (5000 L + 2450(39) )cos 60/(L sin 60)
The boom weighs 2450 and is attached to a friction less pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 39.0 of its length.
What is the tension in the guy wire?
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Thanks in advance
1 answer
1 answer