An aluminum wing on a plane is 30.6 m long when the temperature is 20 oC. At what temperature would the wing be 0.06 m shorter

Answer 1

(T - 20)*(thermal expansion coeff.)* 30.6 = -0.06

Look up the thermal expansion coefficient of aluminum, and solve for T. It will be less than 20 C.

http://hyperphysics.phy-astr.gsu.edu/hbase/tables/thexp.html

Answer 2

-80