Asked by Angela
Assume a family is planning to have three children.
A. What is is the probablity of a family having 2 girls.
B. The probablity of a family having at least 1 boy.
C. List the sample space using a B for Boy and G for girl (Hint there should be 8 possible outcomes).
A. What is is the probablity of a family having 2 girls.
B. The probablity of a family having at least 1 boy.
C. List the sample space using a B for Boy and G for girl (Hint there should be 8 possible outcomes).
Answers
Answered by
Reiny
a) prob (2 girls out of 3) = C(3,2) (1/2)^2 (1/2)
= 3(1/8) = 3/8
b) at least 1 boy --- no "all girls"
prob (all girls) = 1/8
prob (at least 1 boy) = 1 - 1/8 = 7/8
c)
BBB
BBG
BGB
GBB
GGB
GBG
BGG
GGG
= 3(1/8) = 3/8
b) at least 1 boy --- no "all girls"
prob (all girls) = 1/8
prob (at least 1 boy) = 1 - 1/8 = 7/8
c)
BBB
BBG
BGB
GBB
GGB
GBG
BGG
GGG
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