Asked by Phy
A spherical shell of radius R carries a uniform surface charge density (charge per unit area) \sigma. The center of the sphere is at the origin and the shell rotates with angular velocity \omega (in rad/sec) around the z-axis (z=0 at the origin). Seen from below, the sphere rotates clockwise. (See the figure below)
a) (a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of sigma,omega and R:
sigma = 5 times 10^{-4},C/m^2, omega = 4 rad/sec and R = 1 m
b)(b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of sigma, omega , z and R:
sigma = 5 times 10^{-4} {C m}^{-2}, \omega = 4 rad/sec , z= 2.1 m and R =1m
a) (a) Calculate the magnitude of the total current (in A) carried by the rotating sphere for the following values of sigma,omega and R:
sigma = 5 times 10^{-4},C/m^2, omega = 4 rad/sec and R = 1 m
b)(b) Calculate the magnitude of the magnetic field B(z) (in T) that is generated by the circular current of the rotating shell at a point P on the z-axis for the following values of sigma, omega , z and R:
sigma = 5 times 10^{-4} {C m}^{-2}, \omega = 4 rad/sec , z= 2.1 m and R =1m
Answers
Answered by
Anonymous
a) I = Sigma*A*omega
b) B = mu*I/(2*(z-R))
b) B = mu*I/(2*(z-R))
Answered by
Phy
Thanks!! But how to calculate A in the first part??
Answered by
Phy
Wrong formula!!!
Answered by
FLu
I could not get it right with that formula too.
Anonymous, is there chance that you could give us a calculated example with the above numbers?
We could trasfer it into ours, thanks.
Anonymous, is there chance that you could give us a calculated example with the above numbers?
We could trasfer it into ours, thanks.
Answered by
Luy
Please step by step answer, I cannot figure it out too!
Answered by
Mag
Yes, please explain the way guys!
Answered by
Nusa
Anonymous and Phy please help!
Answered by
Anonymous
a) I = Sigma*A*f
f = omega/(2pi)
b) B = mu*I/(2*(z-R))
f = omega/(2pi)
b) B = mu*I/(2*(z-R))
Answered by
FLu
Anonymous, the formula is wrong. Did you get the answer right by the way?
If somebody got the answer could they provide it step by step with numbers though?
thanks
If somebody got the answer could they provide it step by step with numbers though?
thanks
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