draw a diagram. The distance from the observer to the shuttle when the height is y, is
d^2 = 6^2 + y^2
2d dd/dt = 2y dy/dt
when y=8, d=10 so
20 dd/dt = 2(8)(500)
dd/dt = 400 km/hr
An observer is located on the ground 6 kilometers from the point where a space shuttle is launched (vertically). When the shuttle is 8 kilometers high, it is travelling at 500 kilometers per hour. Determine, for that moment, the rate at which the distance between the observer and the shuttle is changing.
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1 answer