Asked by Thien Nguyen
An observer is located on the ground 6 kilometers from the point where a space shuttle is launched (vertically). When the shuttle is 8 kilometers high, it is travelling at 500 kilometers per hour. Determine, for that moment, the rate at which the distance between the observer and the shuttle is changing.
Answers
Answered by
Steve
draw a diagram. The distance from the observer to the shuttle when the height is y, is
d^2 = 6^2 + y^2
2d dd/dt = 2y dy/dt
when y=8, d=10 so
20 dd/dt = 2(8)(500)
dd/dt = 400 km/hr
d^2 = 6^2 + y^2
2d dd/dt = 2y dy/dt
when y=8, d=10 so
20 dd/dt = 2(8)(500)
dd/dt = 400 km/hr
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