Asked by Jon

A 6110-kg bus traveling at 20.0 m/s can be stopped in 24.0 s by gently applying the brakes. What is the average force exerted on the bus in this stop?

I can't figure this one out
Answered by drwls
(Momentum change)= impulse
= (Force) x (time)

Force = M V/(time)
Answered by Anonymous
6110 * 20 whole thing divided by 24 = 5.09*10^3N
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