Asked by jj
find the vertex of 400-16tsquared
Answers
Answered by
Henry
Y = -16t^2 + 400
h = Xv = -B/2A - 0/-32 = 0.
k = Yv = -16*0^2 + 400 = 400.
V(0,400).
h = Xv = -B/2A - 0/-32 = 0.
k = Yv = -16*0^2 + 400 = 400.
V(0,400).
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