Asked by courtney
how many liters are occupied by 0.908 mol of nitrogen at 108 degrees C and 0.858 atm pressure?
Answers
Answered by
PCm
use the ideal gas law by solving for volume v=nRT/p= (.908mol)(.08206)(381K)/(.858atm)=???
R=.08206 latm/molK
Temperature needs to be converted to Kelvin K=108+273
R=.08206 latm/molK
Temperature needs to be converted to Kelvin K=108+273
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