Asked by Torri
Based on information from Harper's Index, 37 out of a random sample of 100 adult Americans who did not attend college believe in extraterrestrials. However, out of a random sample of 100 Americans who did attend college, 41 claim that they believe in extraterrestrials. At the 1% significance level, does this indicate that the proportion of people who attended college who believe in extraterrestrials is higher than the proportion who did not attend college?
Answers
Answered by
MathGuru
Try a z-test for proportions (two samples).
Here is one such formula:
z = (p1 - p2)/(√pq)[√(1/n1 + 1/n2)]
p1 = 41/100 = .41
p2 = 37/100 = .37
p = (x1 + x2)/(n1 + n2) = (41 + 37)/(100 + 100) = 78/200 = .39
q = 1 - p = 1 - .39 = .61
Substitute into the formula:
z = (.41 - .37)/[√(.39)(.61)][√(1/100 + 1/100) = .58 (rounded)
Testing at the 1% significance level for a one-tailed test, you will fail to reject the null. You cannot conclude a difference.
Double check these calculations.
I hope this helps.
Here is one such formula:
z = (p1 - p2)/(√pq)[√(1/n1 + 1/n2)]
p1 = 41/100 = .41
p2 = 37/100 = .37
p = (x1 + x2)/(n1 + n2) = (41 + 37)/(100 + 100) = 78/200 = .39
q = 1 - p = 1 - .39 = .61
Substitute into the formula:
z = (.41 - .37)/[√(.39)(.61)][√(1/100 + 1/100) = .58 (rounded)
Testing at the 1% significance level for a one-tailed test, you will fail to reject the null. You cannot conclude a difference.
Double check these calculations.
I hope this helps.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.