Asked by Liliana
estimate cube root of 25 by linear approximation
f(x+delta(x))= f(x) + (df(x)/x) * deltax
3 + 1/3x^(-2/3) * -2
3 - 2/3x^(-2/3)
3 - (2/3* ((cube root(9)))
is this right? thanks
f(x+delta(x))= f(x) + (df(x)/x) * deltax
3 + 1/3x^(-2/3) * -2
3 - 2/3x^(-2/3)
3 - (2/3* ((cube root(9)))
is this right? thanks