Asked by Michelle
A piece of nickel is placed in a beaker with 350 mL of copper (II) sulfate. Calculate the concentration of the copper (II) sulfate solution.
Initial mass of nickel - 15.5 g
Final mass of nickel - 11.4 g
What do i do with the final and initial masses of nickel?
Initial mass of nickel - 15.5 g
Final mass of nickel - 11.4 g
What do i do with the final and initial masses of nickel?
Answers
Answered by
DrBob222
CuSO4(aq) + Ni ==> NiSO4(aq) + Cu
mass Ni used = 15.5 - 11.4 = ??g Ni.
Convert mass Ni to mols Ni. mols = grams/molar mass.
Mols Ni = mols Cu (from the equation which tells you 1 mol CuSO4 = 1 mol Ni).
mols Cu = mols CuSO4 (since 1 mol Cu is in 1 mol CuSO4).
molarity CuSO4 = mols/L.
mass Ni used = 15.5 - 11.4 = ??g Ni.
Convert mass Ni to mols Ni. mols = grams/molar mass.
Mols Ni = mols Cu (from the equation which tells you 1 mol CuSO4 = 1 mol Ni).
mols Cu = mols CuSO4 (since 1 mol Cu is in 1 mol CuSO4).
molarity CuSO4 = mols/L.
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