Asked by Kendra
A 437.7 N child and a 237.1 N child sit on either end of a 2.5 meter long seesaw.
How far from the 437.7 N child should the pivot be placed to ensure rotational equilibrium? disregard the mass of the seesaw. answer in units of m.
How far from the 437.7 N child should the pivot be placed to ensure rotational equilibrium? disregard the mass of the seesaw. answer in units of m.
Answers
Answered by
bobpursley
I will be happy to critique your thinking.
The sum of the moments about the piviot has to be zero.
The sum of the moments about the piviot has to be zero.
Answered by
drwls
Let the heavier child be x meters from the fulcrum. The lighter child will be 2.5 - x meters from the fulcrum.
For equilibrium,
437.7 x = 237.1 (2.5 -x)
Solve for x.
674.8 x = 592.75
x = 0.88 m
For equilibrium,
437.7 x = 237.1 (2.5 -x)
Solve for x.
674.8 x = 592.75
x = 0.88 m
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