Asked by Julie
Drum major tosses the baton into the air from height of 6feet and initial velocity of 45 ft/sec. What is max height? We are to use ht=h+vt-1/2at^2
Answers
Answered by
Henry
V = Vo + g*t
t = (V-Vo)/g = (0-45)/-32 = 1.41 s.
ht. = 6 + 45*1.41 - 0.5*32*(1.41)^2 = 37.64 Ft.
t = (V-Vo)/g = (0-45)/-32 = 1.41 s.
ht. = 6 + 45*1.41 - 0.5*32*(1.41)^2 = 37.64 Ft.
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