Question

Please help, I need help on these two problems.

Solve the equation.
log3(x − 16) = log3(9x)

e^1 + ln(7)

It appears on the homework that the ln(7) is written like this ^ln(7) but I am still stuck on it.

Thanks!

Answer 1

if logs are the same, the arguments are the same, so

x-16 = 9x
x = -2
But, log(x) is not defined for x<0, regardless of the base

if you mean the entire exponents is 1+ln(7), then

e^(1+ln(7)) = e^1 * e^ln(7) = 7e

by definition, e^ln(n) = n

Answer 2

Log3 15