Asked by Kevin
Neglecting air resistance, how high could a 0.15kg baseball be thrown if it is throw straight up at a speed of 25m/s?
Answers
Answered by
drwls
The mass m is not needed. Potential energy increase equals initial kinetic energy when
m*g*H = m Vo^2/2
H = Vo^2/(2g) = 31.9 meters
m*g*H = m Vo^2/2
H = Vo^2/(2g) = 31.9 meters
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