Asked by Joe

What [PB2+] should be maintained in Pb(NO3) to produce solubility of 1.0*10^-4 mol PbI2/L when PbI2 (s) is added? Ksp for PbI2 is 7.1*10^-9

I can't figure it out...
Answered by DrBob222
.........PbI2(s) ==> Pb^2+ + 2I^-
You want PbI2 = 1E-4; therefore, you want Pb^2+ to be 1E-4M
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