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(9-x)^2 + 4 / 5 when x = 3

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To evaluate the expression \((9 - x)^2 + \frac{4}{5}\) when \(x = 3\), follow these steps:

  1. Substitute \(x = 3\) into the expression: \[ (9 - 3)^2 + \frac{4}{5} \]

  2. Calculate \(9 - 3\): \[ 6 \]

  3. Square the result: \[ 6^2 = 36 \]

  4. Now add \(\frac{4}{5}\) to \(36\): \[ 36 + \frac{4}{5} \]

  5. To add these, convert \(36\) to a fraction with the same denominator: \[ 36 = \frac{180}{5} \]

  6. Now perform the addition: \[ \frac{180}{5} + \frac{4}{5} = \frac{180 + 4}{5} = \frac{184}{5} \]

So, the final result is: \[ \frac{184}{5} \]