9. Cobalt ions form complex ions with water and chloride as shown in the reaction. The left side of the reaction is pink, and the right side of the reaction is blue.

Co(H2O)62+ + 4Cl– + heat ⇄ CoCl42–+ 6H2O

Which statement about the system at equilibrium is correct?

Cooling a purple solution will turn it pink.

Adding water to a purple solution will turn it blue.

Adding hydrogen chloride (HCl) to a blue solution will turn it purple.****

Heating a blue solution will turn it purple.

10. Why are rubber and metal both useful while making wire?(1 point)

Both are good insulators, but one is flexible while the other is rigid.

Both are flexible, but one reflects electromagnetic waves well while the other transmits them.

Both are good insulators, but one is more ductile than the other.

Both are flexible, but one conducts electricity while the other insulates.****

2 answers

I agree with 2 but not 1. The correct answer for #1 is a. This is all about Le Chatelier's principle. Le Chatelier's Principle says "when we do something to a system at equilibrium, it will try to undo what we did to it." Note that the reactants are pink, the products are blue, half way in between is purple.
Co(H2O)62+ + 4Cl– + heat ⇄ CoCl42–+ 6H2O
..................pink.................purple........blue
Cooling a purple solution will turn it pink.
If we cool it the system will try to heat it up so the reaction will shift to the left in order to add heat that we're taking away so it will turn pink. This is the correct answer.

Adding water to a purple solution will turn it blue.
If we add water the reaction will shift to the left in order to use up the water we've added so it will go to pink and not blue.

Adding hydrogen chloride (HCl) to a blue solution will turn it purple.****
Adding Cl^- will make the shift to the right. It is already blue.
Heating a blue solution will turn it purple.
Heating the solution will turn it blue. It's already blue so you won't go through the purple phase.
Wow I actually understood this better than my text books. Thank you.