Question

9 Calcium carbonate, a common material found in chalk and antacids, is shown decomposing in the balanced chemical equation below. Count the number of atoms on the reactant and product side of the equation. How many more atoms are in the products than the reactants? CaCO 3 (s) -> CaO(s) + C*O_{2}(g) A0 B1 c) 2 D3 E4

Answer 1

To analyze the balanced chemical equation for the decomposition of calcium carbonate (CaCO₃):

Reactants: 1 molecule of CaCO₃:

• Calcium (Ca) = 1 atom
• Carbon (C) = 1 atom
• Oxygen (O) = 3 atoms

Total atoms in reactants = 1 (Ca) + 1 (C) + 3 (O) = 5 atoms

Products: 1 molecule of CaO and 1 molecule of CO₂:

• From CaO:
  • Calcium (Ca) = 1 atom
  • Oxygen (O) = 1 atom
• From CO₂:
  • Carbon (C) = 1 atom
  • Oxygen (O) = 2 atoms

Total atoms in products = 1 (Ca) + 1 (C) + 1 (O from CaO) + 2 (O from CO₂) = 5 atoms

Now, let's compare the number of atoms on each side:

• Total atoms in reactants = 5
• Total atoms in products = 5

Difference: Total atoms in products - Total atoms in reactants = 5 - 5 = 0

So, there are no more atoms in the products than in the reactants.

The answer is: A0.