9.50mL of .100M NaOH + 8.00mL of .100M of HC2H3O2. Find the pH.
Okey this is what I did.
8.00-9.50=1.5mL or .0015L
.0015L x .1000 = .00015 moles
.00015/(total volume) = .0085714 M
-log(.0085714)= 2.0669=pOH
14-2.0669 = 11.933
But I'm getting the feeling that this is wrong. Thanks.
2 answers
That looks ok to me except you didn't label 11.93 s the pH. If you find differently, please let me know.
THANKS DR.BOB