To find the integer that is close to the square of \( \frac{9}{4} \), we first compute \( \left( \frac{9}{4} \right)^2 \).
\[ \left( \frac{9}{4} \right)^2 = \frac{9^2}{4^2} = \frac{81}{16} \]
Now we need to convert \( \frac{81}{16} \) to a decimal to better understand its value.
\[ \frac{81}{16} = 81 \div 16 = 5.0625 \]
Thus, \( \frac{9}{4} \) is close to the square root of \( 5.0625 \), and the integer closest to \( 5.0625 \) is \( 5 \).
Therefore, \( \frac{9}{4} \) is close to the square root of the integer \( 5 \).
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