The first one is the difference of cubes
a^3 - b^3 = (a-b)(a^2 + ab + b^2)
so
8y^3 - 27
= (2y-3)(4y^2 + 6y + 9)
the second doesn't factor over the real numbers.
8y^3-27
8y(y^2-27)
x^2+36=
(x+6)(x+6)
Facatoring completely
are they right. corrected if wrong
1 answer