To solve the equation \( 8y - 3 = 15 + 2y \), follow these steps:
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First, let's get all the terms involving \( y \) on one side and constants on the other side. Subtract \( 2y \) from both sides:
\[ 8y - 2y - 3 = 15 \]
This simplifies to:
\[ 6y - 3 = 15 \]
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Next, add 3 to both sides to isolate the term with \( y \):
\[ 6y = 15 + 3 \]
This simplifies to:
\[ 6y = 18 \]
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Finally, divide both sides by 6 to solve for \( y \):
\[ y = \frac{18}{6} \]
This simplifies to:
\[ y = 3 \]
The solution is \( y = 3 \).