(8x^4 - 6x^2) + (2x^2 - 8)(2x^2 + 8)

Question

Simplify
help

Answer 1

(2x^2 - 8)(2x^2 + 8) = 4(x^2-4)(x^2+4) = 4x^4-64

(8x^4 - 6x^2) + (4x^4-64)
= 12x^4 - 6x^2 - 64
= 2(6x^4 - 3x^2 - 32)

can't factor that over the rationals