To solve this system of equations, we can substitute the second equation into the first equation to eliminate y.
Using the second equation, we get:
8x - 3(10 + 4x) = -22
8x - 30 - 12x = -22
-4x - 30 = -22
-4x = -22 + 30
-4x = 8
x = 8/-4
x = -2
Now that we have found the value of x, we can substitute it back into the second equation to find the value of y:
y = 10 + 4(-2)
y = 10 - 8
y = 2
Therefore, the solution to the system of equations is x = -2 and y = 2.
8x−3y= −22
y=10+4x
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