8th Grade Math Solving Linear Equations Online Practice
1. The distance formula can be written as d=rt
, where d= distance traveled, r= the rate of speed, and t= the length of time traveled.
Johan travels 35 miles by bicycle in 1.75 hours. What is Johan’s rate of speed in miles per hour? Explain the solution to the real-world problem.
2. Raji draws a square with a side length of x+5cm. Ava draws a regular hexagon with a side length of x−1cm. The two figures have the same perimeter. Write an equation that allows you to solve for x. What is the value of x?
3. Juwan is thinking of a number. Twice the sum of Juwan's number and 12 is equal to four less than three times Juwan's number. What number is Juwan thinking of?
4. Which of the following equations has exactly one solution?
A. -5z+4=5z+4
B. -5z+3=-5z+3
C. 5z+4=5z+4
D. 5z+4=5z+3
5. Solve for x to determine if the equation has one, none, or infinite solutions.
3(2x+2)−4=−2x+10
6. Which answer gives all the values of z for which the inequality 3x+2≥9−4x is true?
A. x≥1
x greater-than-or-equal-to 1
B. x=1
x equals 1
C. x≤1
x less-than-or-equal-to 1
D. x>1
x greater-than-or-equal-to 1
7. Maluwa solves the inequality 3x+9≥6. Which statement explains the steps she uses to find the solution set of the inequality?
A. Maluwa subtracts 9 from each side of the inequality, divides both sides by 3, and reverses the inequality symbol to obtain the solution ≤−1.
B. Maluwa subtracts 9 from each side of the inequality and then divides both sides by 3 to obtain the solution x≥−1.
C. Maluwa subtracts 9 from both sides of the inequality and then multiplies both sides by 3 to obtain the solution x≥−9.
D. Maluwa adds 9 to each side of the inequality and then divides both sides by 3 to obtain the solution x≥5.
8. Which of the following is the correct solution to the inequality Cx+4≤18, where C is a number greater than 0?
A. C ≤ 14/x
B. x ≤ 14
C. x ≤ 14/C
D. Cx ≤ 14
3 answers
2. The perimeter of a square with side length x+5cm is equal to the perimeter of a regular hexagon with side length x-1cm. The perimeter of a square is 4 * side length, while the perimeter of a regular hexagon is 6 * side length. Therefore, we can write the equation 4(x+5) = 6(x-1) to solve for x. Expanding and simplifying this equation gives us 4x + 20 = 6x - 6. By subtracting 4x and adding 6 to both sides, we get 26 = 2x. Dividing by 2, we find x = 13. Thus, the value of x is 13.
3. Let's represent the number Juwan is thinking of as n. The problem states that twice the sum of Juwan's number and 12 is equal to four less than three times Juwan's number. This can be written as 2(n + 12) = 3n - 4. Expanding and simplifying, we have 2n + 24 = 3n - 4. By subtracting 2n from both sides and adding 4, we get 28 = n. Therefore, Juwan is thinking of the number 28.
4. The equation that has exactly one solution is D. 5z + 4 = 5z + 3. This equation has one solution because when we subtract 5z from both sides, we get 4 = 3, which is not true. Therefore, there are no values of z that satisfy this equation, resulting in exactly one solution.
5. To solve for x, we can begin by distributing the 3 on the left side of the equation. This gives us 6x + 6 - 4 = -2x + 10. Simplifying further, we have 6x + 2 = -2x + 10. By adding 2x to both sides and subtracting 2 from both sides, we obtain 8x = 8. Dividing both sides by 8, we find x = 1. Therefore, the equation has one solution, which is x = 1.
6. The statement that gives all the values of z for which the inequality 3x + 2 ≥ 9 - 4x is true is C. x ≤ 1. To solve this inequality, we can first combine like terms and bring the variables to one side. This gives us 7x + 2 ≥ 9. By subtracting 2 from both sides, we get 7x ≥ 7. Finally, by dividing both sides by 7, we find x ≤ 1. Therefore, the inequality is true when x is less than or equal to 1.
7. Maluwa solves the inequality 3x + 9 ≥ 6 by subtracting 9 from each side of the inequality, resulting in 3x ≥ -3. Then, she divides both sides by 3 to get x ≥ -1. Therefore, the correct statement is B. Maluwa subtracts 9 from each side of the inequality and then divides both sides by 3 to obtain the solution x ≥ -1.
8. The correct solution to the inequality Cx + 4 ≤ 18, where C is a number greater than 0, is C. x ≤ 14/C. To solve this inequality, we can start by subtracting 4 from both sides, giving us Cx ≤ 14. Finally, by dividing both sides by C, we find x ≤ 14/C. Therefore, the correct solution is x ≤ 14/C.
6. A. x greater than equal to 1
6. The correct answer is A. x ≥ 1. The inequality 3x + 2 ≥ 9 - 4x can be solved by combining like terms and bringing all the variables to one side. This gives us 7x + 2 ≥ 9. By subtracting 2 from both sides, we get 7x ≥ 7. Finally, by dividing both sides by 7, we find x ≥ 1. Therefore, the inequality is true when x is greater than or equal to 1.