Asked by Karlee
For the function defined by f(x)=3x^2+5x+2, find the following values.
(a) f(-4)=
(b) f(-x)=
(c) -f(x)=
(d) f(x+h)=
(a) f(-4)=
(b) f(-x)=
(c) -f(x)=
(d) f(x+h)=
Answers
Answered by
Steve
just plug and chug:
f(-4) = 3(16)+5(-4)+2 = 30
f(-x) = 3(-x)^2+5(-x)+2 = 3x^2-5x+2
-f(x) = -(3x^2+5x+2) = -3x^2-5x-2
f(x+h) = 3(x+h)^2+5(x+h)+2
= 3x^2+6hx+3h^2 + 5x+5h + 2
= 3x^2 + (6h+5)x + (3h^2+5h+2)
f(-4) = 3(16)+5(-4)+2 = 30
f(-x) = 3(-x)^2+5(-x)+2 = 3x^2-5x+2
-f(x) = -(3x^2+5x+2) = -3x^2-5x-2
f(x+h) = 3(x+h)^2+5(x+h)+2
= 3x^2+6hx+3h^2 + 5x+5h + 2
= 3x^2 + (6h+5)x + (3h^2+5h+2)
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