Question

Please help!:( What mass of copper would be produced by the reduction of copper(II) ions during pas- sage of 1 ampere of current through a solution of copper(II) sulfate for 89 minutes?
coulombs = A X S
convert 89 mins to seconds

____ c (1 c/1 mol e-) = ___ mol e-
____ mol e- (1 mol/2 e- cu 2+) = mol cu
mol cu x MW cu = g cu
I got 5340. Is that right?

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