Asked by Chad
A marathon runner will burn 1.25x10^7 j during a race. If the calorie content of 12.0 oz. of Gatorade is 80.0 kilocalories, how many ounces of Gatorade must the runner drink to provide enough energy for the race? Note: 1 Calorie=4.184j and "kilo"= 10^3
Answers
Answered by
DrBob222
1.24E7 J x (1 cal/4.184J) = 2.98E6 cal.
12 oz x 2.98E6 cal/80,000 cal = ?oz Gatorade.
12 oz x 2.98E6 cal/80,000 cal = ?oz Gatorade.
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