Asked by Jesha
A 3 cm flower is placed 40 cm from a converging lens with a focal length of 15 cm. What are the orientation, size and type of the image?
Answers
Answered by
Elena
d₀ - object distance
d₁ - image distance
f- focal lenth
1/d₀ +1/d₁ =1/f,
1/d₁ =1/f - 1/d₀ =
= (d₀-f)/ d₀•f,
d₁=d₀•f/(d₀-f)=
=0.4•0.15/(0.4-0.15)=0.24 m,
0.03/0.4 =h/ d₁ ,
h= d₁•0.03/0.4=0.24•0.03/0.4=0.018 m
d₁ - image distance
f- focal lenth
1/d₀ +1/d₁ =1/f,
1/d₁ =1/f - 1/d₀ =
= (d₀-f)/ d₀•f,
d₁=d₀•f/(d₀-f)=
=0.4•0.15/(0.4-0.15)=0.24 m,
0.03/0.4 =h/ d₁ ,
h= d₁•0.03/0.4=0.24•0.03/0.4=0.018 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.