Asked by Cam
A study found that citizens spend on average $1950 per year on groceries with a standard deviation of $100. Assume that the variable is normally distributed.
5. Identify the population mean.
6. Identify the population standard deviation.
7. Find the probability that a sample of 20 citizens will have a mean less than $1800.
8. Find the probability that a sample of 500 citizens will have a mean greater than $2000.
5. Identify the population mean.
6. Identify the population standard deviation.
7. Find the probability that a sample of 20 citizens will have a mean less than $1800.
8. Find the probability that a sample of 500 citizens will have a mean greater than $2000.
Answers
Answered by
PsyDAG
Don't know population mean and SD, but study data is best estimate.
5. $1950
6. $100
7. Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
8. Same process as 7.
5. $1950
6. $100
7. Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.
8. Same process as 7.
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