Asked by HELP
A small block of mass 0.5 kg is released from rest at the top of a ramp of mass 3 kg that sits on a frictionless horizonal surface. When the block leaves the ramp it has a speed of 4 m.s a)what is the recoil velocity of the ramp b) how high is the ramp?
Answers
Answered by
Henry
b. V^2 = Vo^2 + 2g*h
h = (V^2-Vo^2)/2g
h = (4^2-0)/19.6 = 0.82 m.
h = (V^2-Vo^2)/2g
h = (4^2-0)/19.6 = 0.82 m.
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