Ask a New Question

Question

A light rope passing over a frictionless pulley connects two objects. One object has a mass of 10kg. The tension in the rope is 90N. Calculate the acceleration and the mass of the second object.

Object 1
Fg-Ft = ma
100 - 90 - 10*a
10/10 = a
a = 1m/s^2

Object 2
Ft-Fg = ma
90-m10 = ma


I don't know what to do next. Help?
17 years ago

Answers

Related Questions

A light rope is attached to a block with a mass of 6 kg that rests on a horizontal, frictionless sur... A light rope is wrapped several times around a large wheel with a radius of 0.435 m. The wheel? A l... Light passing through water loses 30% of its intensity every metre of water depth. At what depth wil... A light rope is attached to a block with a mass of 10 kg that rests on a horizontal, frictionless su... You observed light passing through lenses and through a set of prisms. Why does refraction occur? You observed light passing through lenses and through a set of prisms. Why does refraction occur? In... The intensity of light passing through a lens can be found using the formula I=Io - Io / csc^2 theta... Rope Q is 12 m longer than Rope P. Rope W is twice as long as Rope P . The total length of the thre... Me: *Talking to a rope* "ROPE, YOU LIED TO ME" Polychromatic light passing through a glass prism is separated into its component frequencies. What...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use