Asked by Grace
Three metals P,Q and R form three ionic solids with three nonmetals X,Y, ands Z respectively as follows P2X, QY2, and RZ3. If their molar solubilities are the same, how are their Ksp values related? Please not only explain but write the respective dissociation.
Answers
Answered by
DrBob222
P2X ==> 2P + X^2-
........2x....x
QY2 ==> Q^2+ + 2Y^-
........x......2x
RZ3 ==> R^3+ + 3Z^-
........x.......3x
Suppose solubility P2X, QY2, RZ3 = 2 just for the fun of it and you can see how Ksp changes.
KP2X = (P)^2(X) = (4)^2(2)= 32
KQY2 = (Q)(Y)^2 = (2)(4)^3 = 32
KRZ3 = (R)(Z)^3 = (2)(6)^3 = 432
........2x....x
QY2 ==> Q^2+ + 2Y^-
........x......2x
RZ3 ==> R^3+ + 3Z^-
........x.......3x
Suppose solubility P2X, QY2, RZ3 = 2 just for the fun of it and you can see how Ksp changes.
KP2X = (P)^2(X) = (4)^2(2)= 32
KQY2 = (Q)(Y)^2 = (2)(4)^3 = 32
KRZ3 = (R)(Z)^3 = (2)(6)^3 = 432
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