Asked by elviria
Suppose we initially had n qubits in the state |ψ⟩=∑x∈{0,1}nαx|x⟩, on which we were going to perform Fourier sampling (i.e. perform Hadamard transform H⊗n and sample). Unfortunately, a clumsy lab assistant mistakenly applied X to one of the qubits and forgot which one it was.
3a. Suppose we initially had n qubits in the state |ψ⟩=∑x∈{0,1}nαx|x⟩, on which we were going to perform Fourier sampling (i.e. perform Hadamard transform H⊗n and sample). Unfortunately, a clumsy lab assistant mistakenly applied X to one of the qubits and forgot which one it was.
.βx′=βx
.βx′=−βx
.βx′=(−1)xiβx
.βx′=(−1)x⋅xβx
βx′=βx⊕ei
3a. Suppose we initially had n qubits in the state |ψ⟩=∑x∈{0,1}nαx|x⟩, on which we were going to perform Fourier sampling (i.e. perform Hadamard transform H⊗n and sample). Unfortunately, a clumsy lab assistant mistakenly applied X to one of the qubits and forgot which one it was.
.βx′=βx
.βx′=−βx
.βx′=(−1)xiβx
.βx′=(−1)x⋅xβx
βx′=βx⊕ei
Answers
Answered by
Final ;)
Hi Elviria, do you have any answer for this exam?
Answered by
Anonymous
ƒÀxŒ=(−1)xiƒÀx
Answered by
Final ;)
what is that?
Answered by
s
Another way to view it is to say that |ψ′⟩=Xi|ψ⟩ where Xi means X applied on the i-th qubit. We would like to claim that the application of Xi to the original state is effectively the same as applying some A to the i-th qubit after the Hadamard transform, i.e, H⊗n|ψ′⟩=H⊗nXi|ψ⟩=AiH⊗n|ψ⟩. What is A?
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XH
Answered by
Anonymous
3A .βx′=(−1)xiβx
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