Please help me. P and Q are two gun placements 1250m apart. T is a target. The angles TPQ and TQP are 73 degree 24' and 68 degree 5' respectively. Find the distance P to the target T.

Answer 1

you know that angle T is 8° 31'

PT/sinQ = 1250/sinT

Answer 2

Hmmm. Bit of a typo there. T is 38°31'