Choose the equation that could be used to find three consecutive integers whose sum is 99
3 answers
What are your choices? What is your answer?
a = first number
b = a + 1 = second number
c = b + 1 = a + 1 + 1 = a + 2 third number
a + b + c = 99
a + a + 1 + a + 2 = 99
3 a + 3 = 99 Subtract 3 to both sides
3 a + 3 - 3 = 99 - 3
3 a = 96 Divide both sides by 3
a = 32
a = first number = 32
b =second number = 32 + 1 = 33
c =third number = 32 + 2 = 34
a + b + c = 32 + 33 + 34 = 99
b = a + 1 = second number
c = b + 1 = a + 1 + 1 = a + 2 third number
a + b + c = 99
a + a + 1 + a + 2 = 99
3 a + 3 = 99 Subtract 3 to both sides
3 a + 3 - 3 = 99 - 3
3 a = 96 Divide both sides by 3
a = 32
a = first number = 32
b =second number = 32 + 1 = 33
c =third number = 32 + 2 = 34
a + b + c = 32 + 33 + 34 = 99
21
5 answers