Question

Write the equations describing the electrode reactions and the net cell reaction for this electrochemical cell containing indium and cadmium:

This is what I have so far:
anode: In(s) --> In^3+ + 3e-
cathode: Cd^2+ + 2e- --> Cd (s)

Need help writing the balanced net reaction!

Answer 1

I believe you need to reverse your cell.
1M Cd/Cd^2+ is 0.403 as an oxidation.
1M In/In^3+ is 0.342 as an oxidation.
Therefore, Cd will be the anode and In the cathode.
3Cd + 2In^3+ ==> 3Cd^2+ + 2In

Answer 2

DrBob222's answer is wrong.

You mean to put Cd/Cd^2+ is -0.403, not 0.403.

Answer is:

3Cd^2+(aq) + 2In(s) --> 3Cd(s) + 2In^3+(aq)


this is right because the short hand notation is:

In(s)|In^3+ (aq)||Cd^2+ (aq)|Cd(s)

And the Anode is always on the left.


~Information valid. College student experience and in the class now.