mols HBr = M x L = ?
mols KOH = mols HBr
MKOH = mols KOH/L KOH
What volume of 0.105 M(molarity)is needed to completely neutralize 25.0 ml of 0.180 M(molarity)HBr according to the equation:
KOH(aq)+ HBr(aq)-> KBr(Aq)+ H2O(L)
1 answer
1 answer