Question

Find the distance between the points with polar coordinates (3, 120°) and (0.5, 49°)? Is the answer 2.88?

Answer 1

(3 , 120)
x = r cos T = 3 (-.5) = - 1.5
y = r sin T = 3 ( .866) = 2.598

(. 5 , 49)
x = .5 (cos 49) = .3280
y = .5 (sin 49) = .3774

change in x = 1.828
change in y = 2.221

d^2 = 1.828^2 + 2.221^2
d = 2.88