horizontal distance is the same.
1*timeinair1=v*timeinair2
but time in air for any fallingobject is sqrt(2h/g)
v=timinair1/timeinair2=sqrt(1.5/1.6)
Baseball player A bunts the ball by hitting it in such a way that it acquires an initial velocity of 1 m/s parallel to the ground. Upon contact with the bat, the ball is 1.5 m above the ground. Payer B wishes to duplicate this bunt, in so far as he also wants to give the ball a velocity parallel to the ground and have his ball travel the same horizontal distance as player A's ball does. However, player B hits the ball when it is 1.6 m above the ground. What is the magnitude of the initial velocity that player B's ball must be given?
1 answer
1 answer