Asked by brenda

logb x= logb(x+2)-logb8
Answered by Rosemary
What is the question?
Answered by Reiny
logb x= logb(x+2)-logb8
logx = log [ (x+2)/8 ] , where all logs are base 8
anti-log it

x = (x+2)/8
8x = x+2
7x = 2

x = 2/7
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