Given :
R(x)= x P(x)
= x (100 e^(-.001x) )
R '(x) = x(-.001)(100) e^(-.001x) + 100 e^(-.001x)
=- .1x e^(-.001x) + 100 e(-.001x)
R' (10) = 1e^(-.01) + 100 e^(-.01)
= .....
you do the button pushing
The unit selling price p (in dollars) and the quantity demanded x (in pairs) of a certain brand of women’s shoes are given by the demand equation
P(x) = 100e^-0.001x f or 0 _< x _< 20,000.
a. Find the revenue function, R. (Hint: R(x) = x(p(x)), since the revenue function is the unit selling price at a demand level of x units times the number of x units demanded.)
b. Find the marginal revenue function, R’.
c. What is the marginal revenue when, x = 10 ?
2 answers
After doing the button pushing the answer is 99.995 is that correct?
0 answers