Ask a New Question

Question

A coil consists of N=105 turns of wire wrapped uniformly around a plastic torus. The inside radius of the torus is r0=0.12 m and the outer radius is r1=0.14 m. Thus, each winding has a diameter d=0.02 m. What is the self-inductance (in H) of this coil? Work in the approximation d≪r0.


12 years ago

Answers

Related Questions

A circular coil of 30 turns and radius 7 cm is placed with its plane oriented at 90 degrees to a mag... a coil having 1000 turns and a length of 3.14cm carries a current of 5A. calculate the magnetomotive... A cirular coil of 27 turns and radius 15.0cm surrounds a long solenoid of radius 4.7cm and 1.00x103... A 0.35 m2 coil with 50 turns rotates at 5 radians per sec2 in a magnetic field of 0.6 Tesla. What is... A 0.35 m2 coil with 50 turns produces a maximum emf of 45 volts in a magnetic field of 0.4 Tesla. Wh... A 0.35 m2 coil with 50 turns produces a maximum emf of 45 volts in a magnetic field of 0.4 Tesla. Wh... A 0.35 m2 coil with 50 turns rotates at 5 radians per sec2 in a magnetic field of 0.6 Tesla. What is... A 0.35 m2 coil with 50 turns rotates at 5 radians per sec2 in a magnetic field of 0.6 Tesla. What is... How come the more turns a coil gets the more magnetic it gets? A coil having : N= 440 turns diameter =1,2mm Mean length= 120mm Inductance= 400micro Henry's C...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use