Question
calculate the concentration of all ions present in 58.7 mg NH4Br in 500 mL of solution
Answers
DrBob222
mols NH4Br = grams/molar mass
Then M NH4Br = mols/0.500L solution.
M = x
(NH4^+) = x
(Br^-) = x
Then M NH4Br = mols/0.500L solution.
M = x
(NH4^+) = x
(Br^-) = x
Anonymous
did you ever find the answer?