Asked by anon
in the past professional baseball was played at the astrodome in Houston, Texas. the astrodome has a maximum height of 63.4 m. the height of a baseball t seconds after it is hit straight up in the air with a velocity of 45 ft/s is given by h = -9.8t + 45t + 1. will a baseball hit straight up with this velocity hit the roof of the astrodome? use the discriminant to explain your answer.
Answers
Answered by
Henry
V = Vo + g*Tr
Tr = (V-Vo)/g = (0-45)/-32 = 1.41 s. =
Rise time or time to reach max. ht.
hmax = -16t^2 + 45t + 1
hmax=-16(1.41)^2 + 45*1.41 + 1=32.64 Ft.
= 9.89 m. Will not hit roof.
Note: Your Eq is not correct.
Tr = (V-Vo)/g = (0-45)/-32 = 1.41 s. =
Rise time or time to reach max. ht.
hmax = -16t^2 + 45t + 1
hmax=-16(1.41)^2 + 45*1.41 + 1=32.64 Ft.
= 9.89 m. Will not hit roof.
Note: Your Eq is not correct.
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