Asked by ramire2
The reaction for the formation of gaseous hydrogen fluoride from hydrogen and fluorine has an equilibrium constant of 1.15x10^2 at a given temperature. In a particular experiment, 3.0 mol of each component was added to a 1.5 L flask. What is the equilibrium concentration of hydrogen fluoride?
So I did 3/1.5L= 2M
H2 + F2 -------> 2HF
2 2 0
-x -x +2x
2x /(2-x)^2 = 1.15 x 10^2
From here, I don't really know how to solve for x to where the HF concentration would equal 5.056 M, which is the right answer.
So I did 3/1.5L= 2M
H2 + F2 -------> 2HF
2 2 0
-x -x +2x
2x /(2-x)^2 = 1.15 x 10^2
From here, I don't really know how to solve for x to where the HF concentration would equal 5.056 M, which is the right answer.
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.