Asked by Jessica
I would also like to see Nathaniels work solved:P I have a similar question
If 1.00 mol each of carbon dioxide and hydrogen is initially injected into a 10.0-L reaction chamber at 986 degrees Celsius, what would be the concentrations of each entity at equilibrium?
CO2(g) + H2(g) „²„³ CO(g) + H2O(g) k = 1.60 for 986 degrees Celsius
Heres my work:
C = n/v
= 0.1 mol/L
CO2(g) + H2(g) „²„³ CO(g) + H2O(g)
I 0.1 0.1 0 0
C -x -x +x +x
E 0.1-x 0.1-x x x
Keq = [CO][H2O]/[CO2][H2]
1.60 = x(x)/(0.1 -x)(0.1 ¡V x)
This is the part I am stuck with please help thanks a lotļ
If 1.00 mol each of carbon dioxide and hydrogen is initially injected into a 10.0-L reaction chamber at 986 degrees Celsius, what would be the concentrations of each entity at equilibrium?
CO2(g) + H2(g) „²„³ CO(g) + H2O(g) k = 1.60 for 986 degrees Celsius
Heres my work:
C = n/v
= 0.1 mol/L
CO2(g) + H2(g) „²„³ CO(g) + H2O(g)
I 0.1 0.1 0 0
C -x -x +x +x
E 0.1-x 0.1-x x x
Keq = [CO][H2O]/[CO2][H2]
1.60 = x(x)/(0.1 -x)(0.1 ¡V x)
This is the part I am stuck with please help thanks a lotļ
Answers
Answered by
DrBob222
Answered.
Answered by
Jessica
It is incorrect, where , sadly I cannot say:(
Answered by
DrBob222
It looks ok to me.
and we can check it.
(0.0558)^2/(0.0442)^2 = 1.594 which is so close to 1.60 (Keq in the problem) it isn't funny. If you are keying into a computer data base, then I suspect there is a problem with s.f. You must decide how many s.f. to report and key those numbers in.
and we can check it.
(0.0558)^2/(0.0442)^2 = 1.594 which is so close to 1.60 (Keq in the problem) it isn't funny. If you are keying into a computer data base, then I suspect there is a problem with s.f. You must decide how many s.f. to report and key those numbers in.
Answered by
Jessica
Hmm.. I will check over if I typed in the correct numbers and I will let you know
Answered by
Laureta
I will rewrite the equaiton making it clearer
CO2(g) + H2(g)<---> CO(g) + H2O(g) k = 1.60 for 986 degrees Celsius
Does this change anything?
CO2(g) + H2(g)<---> CO(g) + H2O(g) k = 1.60 for 986 degrees Celsius
Does this change anything?
Answered by
Jessica
For simplicity, all answers should be correct to two (2) significant figures and not expressed in scientific notation.
The above was also found next to the question
The above was also found next to the question
Answered by
DrBob222
Then 0.056 for CO and H2O should be correct.
And 0.044 for CO2 and H2 should be correct.
And 0.044 for CO2 and H2 should be correct.
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