Asked by Kayleigh
Consider the functions
f(x)= 5x+4/x+3(This is a fraction) and
g(x)= 3x-4/5-x(This is a fraction)
a)Find f(g(x))
b)Find g(f(x))
c)Determine whether the functions f and g are inverses of each other.
f(x)= 5x+4/x+3(This is a fraction) and
g(x)= 3x-4/5-x(This is a fraction)
a)Find f(g(x))
b)Find g(f(x))
c)Determine whether the functions f and g are inverses of each other.
Answers
Answered by
Steve
f(g) = (5g+4)/(g+3)
= (5(3x-4)/(5-x)+4) / ((3x-4)/(5-x)+3)
= x
g(f) = (3f-4)/(5-f)
= (3((5x+4)/(x+3))-4) / (5-((5x+4)/(x+3)))
= x
since f(g) = g(f) = x, they are inverses
= (5(3x-4)/(5-x)+4) / ((3x-4)/(5-x)+3)
= x
g(f) = (3f-4)/(5-f)
= (3((5x+4)/(x+3))-4) / (5-((5x+4)/(x+3)))
= x
since f(g) = g(f) = x, they are inverses
Answered by
Kayleigh
What are the values that need to be excluded?
Answered by
Steve
whatever makes the denominator zero must be excluded, since division by zero is undefined.
So, for f(g), x=5 is not allowed, since g(5) is not defined. In addition, since f(-3) is not defined, any x where g(x) = -3 must also be excluded. Luckily, there is no such x.
Use similar reasoning for g(f).
So, for f(g), x=5 is not allowed, since g(5) is not defined. In addition, since f(-3) is not defined, any x where g(x) = -3 must also be excluded. Luckily, there is no such x.
Use similar reasoning for g(f).
Answered by
Kayleigh
So there are no values to be excluded?
Answered by
Steve
Read what I said. You have to exclude x=5 because g(5) is not defined. Therefore, f(g(5)) is also not defined.
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