Asked by natash
If the warm water in this experiment (Im not quite sure if you need more information) is at 98C, how much heat must be relesed in order for the temperature of 100. mL of water to decrease to 32C ?
Answers
Answered by
DrBob222
q = mass water x specific heat water x delta T.
100 mL H2O = 100 g.
specific heat water = 4.184 J/g*C
delta T = 98-32.
100 mL H2O = 100 g.
specific heat water = 4.184 J/g*C
delta T = 98-32.
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